3x^2-32x-58=0

Solution for 3x^2-32x-58=0 equation:

3x^2-32x-58=0

a = 3; b = -32; c = -58;
Δ = b2-4ac
Δ = -322-4·3·(-58)
Δ = 1720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1720}=\sqrt{4*430}=\sqrt{4}*\sqrt{430}=2\sqrt{430}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-2\sqrt{430}}{2*3}=\frac{32-2\sqrt{430}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+2\sqrt{430}}{2*3}=\frac{32+2\sqrt{430}}{6}
$